获取链接上的参数

function getQueryString() {
  let url = location.search;
  let args = {};

  if (url.indexOf("?") != -1) {
    let str = url.substr(1);
    let strArr = str.split("&");
    for (let i = 0; i < strArr.length; i++) {
      args[strArr[i].split("=")[0]] = decodeURI(strArr[i].split("=")[1]);
    }
  }

  console.log("输出：", args);
  return args;
}

getQueryString();